Order of Reduction
Consider the nonhomogeneous nth order linear ODE with constant
coefficients below.
an y (n) + an−1 y (n−1 ) + · · · + a1 y 0 + a0 y = f (x)
Suppose that S = {y1 (x), y2 (x), . . . , yn (x)} is a fundamental set
for the homogeneous version of the ODE,
an y (n) + an−1 y (n−1) + · · · + a1 y 0 + a0 y = 0.
Then, a particular solution to the nonhomogeneous ODE must
cannot be a linear combination of the functions in S, i.e.
yp (x) = u1 (x)y1 (x) + u2 (x)y2 (x) + · · · + un (x)yn (x)
for some functions u1 (x), u2 (x), . . . , un (x). Matrices
Let A, A1 , A2 , . . . , An
y1 (x)
y10 (x)
00
A = y1 (x)
..
.
(n−1)
y1
be n × n matrices defined by:
y2 (x)
y20 (x)
y200 (x)
..
.
(n−1)
(x) y2
y3 (x)
y30 (x)
y300 (x)
..
.
(n−1)
(x) y3
...
...
...
..
.
yn (x)
yn0 (x)
yn00 (x)
..
.
(n−1)
(x) . . . yn
,
(x)
and Ai is exactly the same as A but with the ith column replaced
by
(0, 0, · · · , 0, f (x))T .
Now, let Wi = |Ai | and recall that W (S) = |A|. Variation of Parameters
For an nth order nonhomogeneous linear ODE, with
S = {y1 (x), y2 (x), . . . , yn (x)} being a fundamental set for the
homogeneous version of the ODE, a particular solution to the ODE
exists of the form,
yp (x) = u1 (x)y1 (x) + u2 (x)y2 (x) + · · · + un (x)yn (x),
where
Z
ui (x) =
for 1 ≤ i ≤ n.
Wi
dx
an (x)W (S) Special Note for this Chapter
In this Chapter, we are only dealing with 2nd order ODEs, so we
just have
W (S) =
y1 (x)
y10 (x)
y2 (x)
y20 (x)
, W1 =
0
f (x)
y2 (x)
y20 (x)
, W2 =
y1 (x)
y10 (x)
0)
f (x)
,
and, thus,
Z
u1 (x) =
−f (x)y2 (x)
dx, u2 (x) =
y1 (x)y20 (x) − y10 (x)y2 (x)
Z
f (x)y1 (x)
dx.
y1 (x)y20 (x) − y10 (x)y2 (x) Example
Find the general solution to the ODE.
y 00 − y 0 = e x . Example
Find the general solution to the ODE.
y 00 − y 0 − 2y = e x . Example
Find the general solution to the ODE.
y 00 − y 0 − 2y = x 2 . Example
Find the general solution to the ODE.
y 00 + 4y 0 + 13y = 4e −2x sin(3x) Example
Show that S = {x −3 , x 2 } are solutions to the homogeneous linear
ODE with NONconstant coefficients
x 2 y 00 + 2xy 0 − 6y = 0.
Now, use Variation of Parameters to find the general solution to
the nonhomogeneous ODE
x 2 y 00 + 2xy 0 − 6y = x 2 .
Variation of Parameters
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