COSMOS Chapter 9 Solution 61 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

436

Pages:

1
Author:

Sean Horton

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 61. Using equation developed on page 491 of text: yP = R = 920 Then Ix I = AA′ yA yA R = γ yA = ρ gyA kg m × 9.81 2 × 3 m × ( 0.55 × 0.25 ) m 2 3 m s = 3722.9 N I AA′ = and 1 ( 0.55 m )( 0.25 m )3 + ( 0.55 m )( 0.25 m )( 3 m )2 12 = 1.238216 m 4 FBD Cover: and yA = ( 3 m )( 0.55 m )( 0.25 m ) = 0.4125 m 3 Then yP = Symmetry implies 1.238216 m 4 = 3.001736 m 0.4125 m 3 FA = FB and FC = FD . Equilibrium: ΣM CD = 0: − ( 0.125 − 0.001736 ) m × ( 3722.9 N ) + ( 0.25 m )( 2FA ) = 0 FA = 917.80 N ΣFx = 0: or FA = FB = 918 N − 2 ( 917.80 N ) + 3722.9 N − 2 FC = 0 FC = 943.65 N or FC = FD = 944 N

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