COSMOS Chapter 6 Solution 166 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
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64

Pages:

1
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 166. FBD jaw AB: ΣFx = 0: Bx = 0 ΣM B = 0: ( 0.01 m ) G − ( 0.03 m ) A = 0 A= ΣFy = 0: G 3 A + G − By = 0 By = A + G = 4G 3 FBD handle ACE: By symmetry and FBD jaw DE: D = A = E y = By = ΣM C = 0: G , Ex = Bx = 0, 3 4G 3 ( 0.105 m )( 240 N ) + ( 0.015 m ) G 4G − ( 0.015 m ) =0 3 3 G = 1680 N W Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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