COSMOS Chapter 6 Solution 89 | Michigan State University - Edubirdie

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COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 89. (a) FBD ACF: Note: BC is a two-force member ΣM F = 0:  1  FBC  = 0,  26  ( 0.1 m )(120 N ) − ( 0.3 m )  B x = 200 N FBC = 40 26 N, B y = 40.0 N ΣFx = 0: (b) FBD BCE: ΣFy = 0: ( ) 5 40 26 N − Fx = 0, 26 ( Fx = 200 N ) 1 40 26 N = 0, 26 Fy − 120 N − Fy = 160.0 N ! ! ! ! Note ACF is a two-force member ΣM B = 0:  1  FCF  = 0,  5  ( 0.4 m )(120 N ) − ( 0.3 m )  FCF = 160 5 N, Fx = 320 N Fy = 160.0 N ΣFx = 0: Bx − ΣFy = 0: ( ( ) 2 160 5 N = 0, 5 B x = 320 N ! ! ! ) 1 160 5 N − 120 N − B y = 0 5 B y = 40.0 N ! (c) Moving the 120 N force from D to E does not affect the reactions. The answers are the same as in part (b). ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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