University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

284

Pages:

1
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 37. Geometry: FBD AB: θ = cos −1 L L L + − 2 4 2 = 60° L 2 For min a L slip will impend to right and reactions will be at φ s = tan −1 µ s = tan −1 ( 0.35 ) = 19.2900° from normal. Note: AB is a three-force member CD = a tan ( 60 + φs ) = ( L − a ) tan ( 60° − φ s ) a tan ( 79.29° ) = ( L − a ) tan ( 40.71° ) 6.1449 = L −1 a a = 0.13996 L min Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. a = 0.1400 W L