COSMOS Chapter 3 Solution 144 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

300

Pages:

1
Author:

nismChiehearijzf

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 144. M A = rE/ A × TDE (a) Have rE/ A = ( 92 in.) j where TDE = λ DETDE = ( 24 in.) i + (132 in.) j − (120 in.) k 360 lb ( ) ( 24 )2 + (132 )2 + (120 )2 in. = ( 48 lb ) i + ( 264 lb ) j − ( 240 lb ) k i j k ∴ M A = 0 92 0 lb ⋅ in. = − ( 22,080 lb ⋅ in.) i − ( 4416 lb ⋅ in ) k 48 264 −240 or M A = − (1840 lb ⋅ ft ) i − ( 368 lb ⋅ ft ) k M A = rG/ A × TCG (b) Have rG/ A = (108 in.) i + ( 92 in.) j where TCG = λ CGTCG = − ( 24 in.) i + (132 in.) j − (120 in.) k ( 24 )2 + (132 )2 + (120 )2 in. ( 360 lb ) = − ( 48 lb ) i + ( 264 lb ) j − ( 240 lb ) k i j k ∴ M A = 108 92 0 lb ⋅ in. −48 264 −240 = − ( 22, 080 lb ⋅ in.) i + ( 25,920 lb ⋅ in.) j + ( 32,928 lb ⋅ in.) k or M A = − (1840 lb ⋅ ft ) i + ( 2160 lb ⋅ ft ) j + ( 2740 lb ⋅ ft ) k .

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