COSMOS Chapter 8 Solution 121 | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
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51

Pages:

1
Author:

Quintin Ware

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 121. Geometry and force notation: θ = sin −1 βC = π − 5 in. π = 30° = rad, so contact angles are: 10 in. 6 π 6 = 5π π π 2π = , βD = + , 6 2 6 3 βE = π 2 (a) D and E fixed, so slip at these surfaces, For maximum WA , slip impends on C. WA = T1e µs βC , T2 = T1e µk β D , 16 lb = T2e µk β E so WA = (16 lb ) e = (16 lb ) e − µ k ( β D + β E ) µ s βC e ( ) e0.20( 56π ) −0.15 76π = 15.5866 lb WA max = 15.59 lb (b) C and D fixed, so slip at these surfaces—impending slip on E T1 = WAe µk βC , T2 = T1e µk β D , so WA = (16 lb ) e − µk ( βC + β D ) µ s β E e T2 = (16 lb ) e µs β E = (16 lb ) e ( ) e0.20( π2 ) −0.15 32π WA = 10.8037 lb, Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. WA max = 10.80 lb

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