COSMOS Chapter 8 Solution 83 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
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440

Pages:

1
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 83. FBD link AB: Note: That AB is a two-force member. For impending motion, the pin forces are tangent to the friction circles. r θ = sin −1 f 25 in. where ( rf = rp sin φs = rp sin tan −1 µ s ) * ( ) = (1.5 in.) sin tan −1 0.2 = 0.29417 in. Then θ = sin −1 0.29417 in. = 1.3485° 12.5 in. (b) Rvert = R cosθ θ = 1.349° Rhoriz = R sin θ Rhoriz = Rvert tan θ = ( 50 kips ) tan1.3485° = 1.177 kips (a) Rhoriz = 1.177 kips NOTE FOR PROBLEMS 8.75–8.89 ( ) Note to instructors: In this manual, the simplification sin tan −1 µ ≈ µ is NOT used in the solution of journal bearing and axle friction problems. While this approximation may be valid for very small values of µ , there is little if any reason to use it, and the error may be significant. For example, in Problems 8.76–8.79, µ s = 0.50, and the error made by using the approximation is about 11.8%. Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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