COSMOS Chapter 6 Solution 90 | Answer Key - Edubirdie

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Michigan State University
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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2024
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COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 90. (a) FBD AF: Note: BC is a two-force member ΣM F = 0:  1  FBC  − 48 N ⋅ m = 0,  26  ( 0.3 m )  FBC = 160 26 N so B x = 800 N B y = 160.0 N (b & c) FBD BCE: ΣFx = 0: Fx − 800 N = 0, ΣFy = 0: − Fy + 160 N = 0, Fx = 800 N Fy = 160.0 N ! ! ! ! Note: ACF is a two-force member, and that the application point of the couple is immaterial. ΣM B = 0:  1  FCF  − 48 N ⋅ m = 0  5  ( 0.3 m )  FCF = 160 5 N, Fx = 320 N Fy = 160.0 N ΣFx = 0: 320 N − Bx = 0, ΣFy = 0: −160 N + By = 0, Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. B x = 320 N B y = 160.0 N ! ! ! !

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