COSMOS Chapter 6 Solution 140 - Edubirdie

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Michigan State University
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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2024
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COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 140. FBD top handle: By symmetry the horizontal force at F must be zero ΣFx = 0: Dx = 0 ΣM F = 0: ( 0.015 m ) Fy − ( 0.185 m )(135 N ) = 0 Dy = 1665 N FBD ABD: ΣM B = 0: ( 40 mm ) (1665 N ) − ( 30 mm ) A = 0 A= 2220 N A= 2.22 kN W Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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