COSMOS Chapter 8 Solution 81 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

301

Pages:

1
Author:

Sean Horton

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 81. Pulley FBD’s: rp = 30 mm Left: ( rf = raxle sin φk = raxle sin tan −1 µ k ) * ( = ( 5 mm ) sin tan −1 0.2 ) = 0.98058 mm Left: ΣM C = 0: Right: ( rp − rf ) ( 600 lb ) − 2rpTAB = 0 TAB = or 30 mm − 0.98058 mm ( 600 N ) = 290.19 N 2 ( 30 mm ) TAB = 290 N ΣFy = 0: 290.19 N − 600 N + TCD = 0 TCD = 309.81 N or TCD = 310 N Right: ( rp + rf ) TCD − ( rp − rf ) TEF ΣM G = 0: or TEF = =0 30 mm + 0.98058 mm ( 309.81 N ) = 330.75 N 30 mm − 0.98058 mm TEF = 331 N NOTE FOR PROBLEMS 8.75–8.89 ( ) Note to instructors: In this manual, the simplification sin tan −1 µ ≈ µ is NOT used in the solution of journal bearing and axle friction problems. While this approximation may be valid for very small values of µ , there is little if any reason to use it, and the error may be significant. For example, in Problems 8.76–8.79, µ s = 0.50, and the error made by using the approximation is about 11.8%. Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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