COSMOS Chapter 6 Solution 5 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
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1
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COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 5. FBD Truss: ΣFx = 0 : Cx = 0 By symmetry: C y = D y = 6 kN Joint FBDs: Joint B: ΣFy = 0: − 3 kN + 1 FAB = 0 5 FAB = 3 5 = 6.71 kN T W Joint C: ΣFx = 0: ΣFy = 0: Joint A: ΣFx = 0: ΣFy = 0: 2 FAB − FBC = 0 5 FBC = 6.00 kN C W 3 FAC = 0 5 FAC = 10.00 kN C W 6 kN − 6 kN − 4 FAC + FCD = 0 5 FCD = 2.00 kN T W  1  3  − 2 3 5 kN  + 2  10 kN  − 6 kN = 0 check 5   5  By symmetry: FAE = FAB = 6.71 kN T W FAD = FAC = 10.00 kN C W FDE = FBC = 6.00 kN C W Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell .

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