COSMOS Chapter 4 Solution 21 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

319

Pages:

1
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 21. Free-Body Diagram: (a) ΣΜ Βx = 0 : or Fsp =  2.4 in.  −  A − (0.9 in.)Fsp = 0  cosα  8 lb = kx = k (1.2 in.) cos 30° Solving for k: k = 7.69800 lb/in. k = 7.70 lb/in. (b) 8 lb  =0  cos30°  ( 3 lb ) sin 30° + Bx +  ΣFx = 0: Bx = −10.7376 lb or − ( 3 lb ) cos 30° + B y = 0 ΣFy = 0: By = 2.5981 lb or B= ( −10.7376 )2 + ( 2.5981)2 θ = tan −1 Therefore: = 11.0475 lb, and 2.5981 = 13.6020° 10.7376 B = 11.05 lb 13.60°

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