COSMOS Chapter 8 Solution 99 | Answer Key - Edubirdie

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Michigan State University
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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2024
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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 99. FBD wheel: ( ) rf = raxle sin φ = raxle sin tan −1 µ , rw = rf sin θ + b tan θ For small θ , sin θ tan θ , so tan θ R cosθ − ΣFy = 0: rf + b rw W =0 4 − R sin θ + ΣFx = 0: P =0 4 P W Solving: tan θ = so P = W tan θ = W (a) For impending slip, use µ s , µs or µk rf + b rw  0.5 in.  −1 rf =   sin tan 0.12 = 0.029786 in.  2  ( so P = ( 500 lb ) ) 0.02986 in. + 0.25 in. = 55.96 lb 2.5 in. P = 56.0 lb (b) For constant speed, use µ k ,  0.5 in.  −1 rf =   sin tan 0.08 = 0.019936 in.  2  so P = ( 500 lb ) ( ( 0.019936 + 0.25) in. 2.5 in. ) = 53.99 lb P = 54.0 lb Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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