COSMOS Chapter 6 Solution 163 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
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373

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1
Author:

Caroline Mcfarland

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 163. FBD Frame: ΣM E = 0: ( 3.75 in.) Bx + (8.75 in.)( 75 lb ) = 0 Bx = 175 lb FBD member ACE: ΣFx = 0: Ex − Bx = 0 ΣFy = 0: E y + By − 75 lb = 0 B x = 175.0 lb W E x = 175.0 lb W By = 75 lb − E y ΣM C = 0: Thus − (1.25 in.)( 75 lb ) + ( 3.75 in.)(175 lb ) − ( 4.5 in.) E y = 0 E y = 125.0 lb W B y = 50.0 lb W By = 75 lb − 125 lb = −50 lb Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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