COSMOS Chapter 4 Solution 31 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

362

Pages:

1
Author:

Dixie Summers

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 31. Free-Body Diagram: Geometry: Distance BC = (7.2)2 + (3)2 = 7.8 in. Distance CD = (10.8)2 + (3)2 = 11.2089 in. Equilibrium for bracket: 7.2   3   10.8  T  ( 4 in.) −  T  ( 9 in.) +  T  ( 4 in.)  7.8   7.8   11.2089  (10 lb )( 9 in.) −  ΣM A = 0: 3   T  ( 9 in.) = 0 +  11.2089  or T = 101.0 lb T = 101.014 lb  7.2   10.8  Ax +   (101.014 lb ) −   (101.014 lb ) = 0 7.8    11.2089  ΣFx = 0: Ax = 4.0853 lb ΣFy = 0: 3  3    Ay +   (101.014 lb ) +   (101.014 lb ) + 10 lb = 0  7.8   11.2089  Ay = − 75.887 lb Ax2 + Ay2 = Thus: A= and θ = tan −1 Ay Ax ( 4.0853)2 + ( − 75.887 )2 = tan −1 = 75.997 lb 75.887 = 86.919° 4.0853 ∴ A = 76.0 lb 86.9°

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