COSMOS Chapter 6 Solution 102 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
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201

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1
Author:

Nicole Wang

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 102. FBD Stool:  w 1 N = ( 56 kg )  9.81  = 274.68 N 2 2 kg   ΣM A = 0: ( 0.350 m ) By − ( 0.150 m )( 274.68 N ) = 0, By = 117.72 N FBD BE: ΣM E = 0:  1  FFG  = 0  2  (1.25 m )(117.72 N ) − ( 0.15 m )  FFG = 98.1 2 N ΣFx = 0: ΣFy = 0: Ex − 1 (98.1 2) N = 0, 2 − Ey + E x = 98.1 N W 1 (98.1 2 N) + 117.72 N = 0 2 E y = 215.82 N, Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. E y = 216 N W

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