COSMOS Chapter 8 Solution 45 | Michigan State University - Edubirdie

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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 45. FBD pin A: ΣFx = 0: ΣFy = 0: Solving: 12 3 FAB − FAC = 0 13 5 5 4 FAB + FAC − P = 0 13 5 FAB = 13 P, 21 FAC = 20 P 21 FBD B: ΣFx = 0: NB − 12 13 ⋅ P = 0, 13 21 NB = For Pmin slip of B impends down, so FB = µ s N B = ΣFy = 0: FBD C: 11 12 5 13 ⋅ P− ⋅ P − 18 lb = 0, 20 21 13 21 12 P 21 11 NB 20 Pmin = 236.25 lb (For P < 236.25 lb, A will slip down) ΣFy = 0: NC − 80 lb − 4 20 16 ⋅ P = 0, NC = 80 lb + P 5 21 21 For Pmax slip of C impends to right, FC = µ s NC FC = or ΣFx = 0: 11  16  44 P  = 44 lb + P  80 lb + 20  21  105 3 20 ⋅ P − FC = 0, 5 21 12 44 P = 44 lb + P 21 105 Pmax = 288.75 lb ∴ equilibrium 236 ≤ P ≤ 289 W Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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