COSMOS Chapter 3 Solution 93 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

209

Pages:

1
Author:

Dixie Summers

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 93. Have ΣF : TAB = F where TAB = TAB JJJG AB AB = (10.5 kN ) − i − 4.75j + 2k ( −1)2 + ( − 4.75)2 + ( 2 )2 = − ( 2 kN ) i − ( 9.5 kN ) j + ( 4 kN ) k F = − ( 2.00 kN ) i − ( 9.50 kN ) j + ( 4.00 kN ) k So that Have ΣM O : rA × TAB = M i j k 3 4.75 0 kN ⋅ m = M − 2 − 9.5 4 ∴ M = (19 kN ⋅ m ) i − (12 kN ⋅ m ) j − (19 kN ⋅ m ) k M = (19.00 kN ⋅ m ) i − (12.00 kN ⋅ m ) j − (19.00 kN ⋅ m ) k .

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