COSMOS Chapter 8 Solution 64 | Answer Key - Edubirdie

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Michigan State University
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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2024
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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 64. ( ) ( ) WA = (10 kg ) 9.81 m/s 2 = 98.1 N, WB = ( 50 kg ) 9.81 m/s 2 = 490.5 N Slip must impend at all surfaces simultaneously, F = µ s N FBD I: A + B ΣFy = 0: N B − 150 N − 98.1 N − 490.5 N = 0, impending slip: FBD II: A N B = 738.6 N FB = µ s N B = ( 738.6 N ) µ s N A = ( 738.6 N ) µ s ΣFx = 0: N A − FB = 0, ΣFy′ = 0: FAB + ( 738.6µ s ) N  sin 20° − (150 N + 98.1 N ) cos 20° = 0 FAB =  233.14 − ( 252.62 ) µ s  N ΣFx′ = 0: ( 738.6µ s ) N  cos 20° − (150 N + 98.1 N ) sin 20° − N AB = 0 N AB = 84.855 + ( 694.06 ) µ s  N µs = FAB 233.14 − 252.62µ s = N AB 84.855 + 694.06µ s µ s2 = 0.48623µ s − 0.33591 = 0 µ s = − 0.24312 ± 0.62850 Positive root Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. µ s = 0.385

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