COSMOS Chapter 4 Solution 110 | Answer Key - Edubirdie

University:
Michigan State University
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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2024
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1
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COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 110. Free-Body Diagram: ΣM O = 0: ( 0.75 ft ) i × ( Ay j + Azk ) + ( 3.75 ft ) i × ( By j + Bzk ) + ( 2.25 ft ) i + ( 3 ft ) k  × ( − 27 lb ) j + ( 4.5 ft ) i + ( 5.25 ft ) k  × C y j = 0 or ( 0.75 ft ) Ayk − ( 0.75 ft ) Az j + ( 3.75 ft ) Byk − ( 3.75 ft ) Bz j − ( 2.25 ft )( 27 lb ) k + ( 3 ft )( 27 lb ) i + ( 4.5 ft ) C yk − ( 5.25 ft ) C y i = 0 Setting the coefficients of the unit vectors equal to zero: i: ( 27 lb )( 3 ft ) − C y ( 5.25 ft ) = 0 C y = 15.4286 lb k: ( 27 lb )(1.5 ft ) + By ( 3 ft ) − (15.4286 lb )( 3.75 ft ) = 0 By = − 5.78575 lb ΣFy = 0: Ay − 5.78575 lb − 27 lb + 15.4286 lb = 0 Ay = 17.3572 lb Therefore: (a) (b) (c) A y = 17.36 lb B y = 5.79 lb C y = 15.43 lb

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