COSMOS Chapter 4 Solution 65 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
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374

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1
Author:

garciavelascogr11

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 65. Free-Body Diagram: Geometry: EF = ( 2.4 tan 30° + 0.9 ) in. AF = EF tan 30° tan φ = 0.9 ( 2.4 tan30° + 0.9 ) tan 30° + 2.4 φ = 13.6019° Equilibrium: force triangle Using the law of sines on the force triangle: Fsp 3 lb B = = sin120° sin ( 60° − φ ) sinφ B = 11.05 lb Fsp = 9.2376 lb (a) Fsp = kx 9.2376 lb = k (1.2 in.) Solving for k: k = 7.698 lb/in. (b) or k = 7.70 lb/in. B = 11.05 lb 13.60°

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