University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2023
Views:

34

Pages:

1
Author:

Nicole Wang

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 20. Free-Body Diagram: From free-body diagram of lever BCD ΣM C = 0: TAB ( 50 mm ) − P ( 75 mm ) = 0 ∴ TAB = 1.5P (1) ΣFx = 0: 0.6TAB + P − Cx = 0 ∴ C x = P + 0.6TAB (2) Cx = P + 0.6 (1.5P ) = 1.9 P From Equation (1) ΣFy = 0: 0.8TAB − C y = 0 ∴ C y = 0.8TAB (3) C y = 0.8 (1.5P ) = 1.2 P From Equation (1) From Equations (2) and (3) C = C x2 + C y2 = 1.9 P 2 + 1.2 P ) = 2.2472 P 2 Since Cmax = 500 N, ∴ 500 N = 2.2472Pmax or Pmax = 222.49 lb or P = 222 lb

COSMOS Chapter 4 Solution 20

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