University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

45

Pages:

1
Author:

omiliar74be

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 194. (a) Have I AA′ = I GG′ + mra2 ra + rb = 290 mm = 0.29 m and I BB′ = I GG′ + mrb2 ( I BB′ − I AA′ = m rb2 − ra2 Subtracting ( 41 − 78) g ⋅ m 2 ) = (2000 g) ( rb + ra )( rb − ra ) or − 37 = (2000) (0.29) ( rb − ra ) or ra − rb = 63.793 × 10−3 m now ra + rb = 0.29 m so that 2ra = 0.35379 m ra = 0.17689 m or ra = 176.9 mm I AA′ = I GG′ + mra2 (b) Have Then I GG′ = 78 g ⋅ m 2 − (2000 g) (0.17689 m) 2 = 15.420 g ⋅ m 2 Finally, 2 kGG ′ = I GG′ 15.420 g ⋅ m 2 = = 0.007710 m 2 m 2000 g kGG′ = 0.08781 m kGG′ = 87.8 mm

COSMOS Chapter 9 Solution 194

of 1

Description

Free up your schedule!

Take 5 seconds to unlock