University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

224

Pages:

1
Author:

Kundulu8mbj

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 50. (a) Free-Body Diagram: ΣFx = 0: Ex = 0 ΣFy = 0: E y − 16.2 kN − 5.4 kN − 18 kN = 0 Ey = 39.6 kN ΣM E = 0: M E + (16.2 kN)(4.8 m) + (5.4 kN)(2.6 m) − (18 kN)(1.5 m) = 0 M E = − 64.8 kN ⋅ m (b) or E = 39.6 kN or ME = 64.8 kN. m Free-Body Diagram: ΣFx = 0: Ex = 0 ΣFy = 0: E y − 16.2 kN − 5.4 kN = 0 Ey = 21.6 kN ΣM E = 0: or E = 21.6 kN ME + (16.2 kN)(4.8 m) + (5.4 kN)(2.6 m) = 0 M E = − 91.8 kN ⋅ m or ME = 91.8 kN ⋅ m