COSMOS: Complete Online Solutions Manual Organization System
Chapter 4, Solution 84.
Free-Body Diagram:
From the free-body diagram it follows that
tan θ =
9.6 − 8sin20°
8cos20°
θ = 42.397°
Also:
BE = 20sin 20° + ( 20cos 20° ) tan 42.397° = 12sin 20° (12cos 20° ) tan φ
φ = 60.456°
Then using the law of sines on the force triangle:
TAD
C
60 lb
=
=
sin ( 90° − φ ) sin ( 90° + θ ) sin (φ − θ )
TAD
C
60 lb
=
=
cos 60.456° cos 42.397° sin18.059°
(a)
TAD = 95.438 lb
(b)
C = 142.935 lb
or TAD = 95.41 lb
or C = 142.935 lb
60.5°
COSMOS Chapter 4 Solution 84
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