COSMOS: Complete Online Solutions Manual Organization System
Chapter 3, Solution 112.
(a)
Have
R = ΣF
R = ( 25 N )( cos 40°i + sin 40° j) − (15 N ) i − (10 N ) j
= ( 4.1511 N ) i + ( 6.0696 N ) j
R =
( 4.1511)2 + ( 6.0696 )2
= 7.3533 N
6.0696
θ = tan −1
4.1511
= 55.631°
R = 7.35 N
or
55.6°
(a) and (b)
(b)
From
M B = ΣM B = dRy
where
M B = − ( 25 N ) cos 40° ( 0.375 m ) sin 50°
− ( 25 N ) sin 40° ( 0.375 m ) cos 50°
+ (15 N ) ( 0.150 m ) sin 50° − (10 N )( 0.150 m )
+ 6.25 N ⋅ m
∴ M B = −2.9014 N ⋅ m
and
d =
=
MB
Ry
−2.9014 N ⋅ m
6.0696 N
= 0.47802 m
or
(c)
d = 478 mm to the left of B
From M B = rD/B × R
− ( 2.9014 N ⋅ m ) k = ( −d1 cos 50°i + d1 sin 50° j)
× ( 4.1511 N ) i + ( 6.096 N ) j
− ( 2.9014 N ⋅ m ) k = − ( 7.0814 d1 ) k
∴ d1 = 0.40972 m
or d1 = 410 mm from B along line AB
or 34.7 mm above and to left of A
.
COSMOS Chapter 3 Solution 112
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