University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

122

Pages:

1
Author:

Athena Harrison

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 119. FBD Blade: ΣFy = 0: FBD ABC: ΣM C = 0: 3 kN − 12 FBD = 0: FBD = 3.25 kN C 13 0.045 m + ( 0.3 m ) sin 30°  P sin 30° + 0.030 m + ( 0.3 m ) cos 30° P cos 30° − ( 0.045 m ) − ( 0.03 m ) 5 ( 3.25 kN ) 13 12 ( 3.25 kN ) = 0 13 P = 0.41968 kN so ΣFx = 0: P = 420 N (a) − ( 0.41968 kN ) sin 30° + 5 ( 3.25 kN ) − Cx = 0 13 C x = 1.04016 kN ΣFy = 0: − ( 0.41968 kN ) cos30° + 12 ( 3.25 kN ) − C y = 0 13 C y = 2.6365 kN so (b) Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. C = 2.83 kN 68.5°

COSMOS Chapter 6 Solution 119

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