COSMOS: Complete Online Solutions Manual Organization System
Chapter 9, Solution 49.
From Fig. 9.13A
Area = A = 4.75 in 2
I x′ = 17.4 in 4
I y′ = 6.27 in 4
(
)
2
I x = 2 I x′ + Ad 2 = 2 17.4 in 4 + 4.75 in 2 ( 3.00 − 1.990 ) in 2
= 2 17.4 in 4 + 4.8455 in 4 = 44.491 in 4
I x = 44.5 in 4
k x2 =
Ix
44.491 in 4
=
= 4.683 in 2
A 2 4.75 in 2
(
k x = 2.16 in.
)
(
)
2
I y = 2 I y′ + Ad 2 = 2 6.27 in 4 + 4.75 in 2 ( 2.25 − 0.987 ) in 2
= 2 6.27 in 4 + 7.5771 in 4 = 27.694 in 4
I y = 27.7 in 4
k y2 =
Iy
A
=
27.694 in 4
(
2 4.75 in 2
)
= 2.9152 in 2
k y = 1.707 in.
COSMOS Chapter 9 Solution 49
of 1
Report
Tell us what’s wrong with it:
Thanks, got it!
We will moderate it soon!
Free up your schedule!
Our EduBirdie Experts Are Here for You 24/7! Just fill out a form and let us know how we can assist you.
Take 5 seconds to unlock
Enter your email below and get instant access to your document