University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

243

Pages:

1
Author:

Lily Callahan

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 153. Note: The couples exerted by the two yokes on the crosspiece must be equal and opposite. Since neither yoke can exert a couple along the arm of the crosspiece it contacts, these equal and opposite couples must be normal to the plane of the crosspiece. If the crosspiece arm attached to shaft CF is horizontal, the plane of the crosspiece is normal to shaft AC, so couple M C is along AC. FBDs shafts with yokes: (a) ΣM x = 0: FBD CDE: M C cos30° − 50 N ⋅ m = 0 M C = 57.735 N ⋅ m FBD BC: ΣM x′ = 0: M A − M C = 0 (b) M A = 57.7 N ⋅ m W ΣM C = 0: M A i′ + ( 0.5 m ) Bz j′ − ( 0.5 m ) By′ k = 0 ΣF = 0: B + C = 0 so B = 0W C=0 FBD CDF : ΣM Dy = 0: − ( 0.6 m ) Ez + ( 57.735 N ⋅ m ) sin 30° = 0 E z = 48.1 N k ΣFx = 0: Ex = 0 ΣM Dz = 0: ( 0.6 m ) E y = 0 Ey = 0 0 ΣF = 0: C + D + E = 0 Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. so E = ( 48.1 N ) k W D = −E = − ( 48.1 N ) k W

COSMOS Chapter 6 Solution 153

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