University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2020
Views:

326

Pages:

1
Author:

Arielle Armstrong

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 74. Free-Body Diagram: Let E be the intersection of the lines of action of the three forces acting on the tool. From the free-body diagram, using law of sines: 6 in. + ( 0.76 in.) tan 35° L = sin 95° sin 30° L = 13.0146 in. Also: yBD = L − y AE − 0.88 in. = 13.0146 in. − 0.76 in. − 0.88 in. cos 35° = 11.2068 in. And  1.8 in.    yBD  α = tan −1   1.8 in.  = tan −1   = 9.1247°  11.2086 in.  Then from the force triangle and using the law of sines: B 14 lb = sin150° sin 9.1247° Solving for B: B = 44.141 lb, or on the member B = 44.141 lb 80.9°, and on the lid B = 44.1 lb 80.9°

COSMOS Chapter 4 Solution 74

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