University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

269

Pages:

1
Author:

suzshikn5

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 150. Have ΣF : PAB = FC where PAB = λ AB PAB = ( 2.0 in.) i + ( 38 in.) j − ( 24 in.) k 44.989 in. ( 45 lb ) or FC = ( 2.00 lb ) i + ( 38.0 lb ) j − ( 24.0 lb ) k Have ΣM C : rB/C × PAB = M C i j k M C = 2 29.5 −33 0 lb ⋅ in. 1 19 −12 = ( 2 lb ⋅ in.) {( −33)( −12 ) i − ( 29.5 )( −12 ) j + ( 29.5 )(19 ) − ( −33)(1)  k } or M C = ( 792 lb ⋅ in.) i + ( 708 lb ⋅ in.) j + (1187 lb ⋅ in.) k .

COSMOS Chapter 3 Solution 150

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