COSMOS Chapter 6 Solution 26

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 26. Joint FBDs: Joint A: ΣFy = 0: 9 FAC − 1.8 kips = 0, 41 40 FAB − 8.20 kips = 0, 41 ΣFx = 0: DE = ΣFy = 0: FBD = 8.00 kips C ! FBC = 0.6 kips, and then Note: FAB = 8.00 kips C ! FBD = FAB By inspection of joint B, Joint C: FAC = 8.20 kips T ! FBC = 0.600 kips C ! 9.2 (4.5 ft) = 2.07 ft, 20 CE = 4.14 ft = 2 DE 1 FCD − 0.6 kips = 0, 5 FCD = 0.6 5 kips FCD = 1.342 kips T ! ΣFx = 0: 8.2 kips + ( ) 2 0.6 5 kips − FCE = 0 5 FCE = 9.20 kips C ! Joint D: ΣFy = 0: ( ) 40 2 0.6 5 kips = 0 ( FDG − 8.2 kips ) − 41 5 FDG = 9.43 kips T ! ΣFx = 0: FDE − ( ) 9 1 0.6 5 kips = 0 ( 9.43 kips − 8.2 kips ) − 41 5 FDE = 0.330 kips C ! Joint E: ΣFy = 0: ΣFx = 0: 5 FEG − 0.33 kips = 0, 13 FEG = 0.858 kips T ! 12 ( 0.858 kips ) + 9.2 kips − FEF = 0 13 FEF = 9.992 kips, Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. FEF = 9.99 kips C ! COSMOS: Complete Online Solutions Manual Organization System Joint F: By vertical symmetry FFG = FFH ΣFx = 0: 4  9.992 kips − 2  FFG  = 0, 5   FFG = 5.995 kips FFG = FFH = 6.00 kips C ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.