University:
Missouri State University
Course:
CHM 160 | General Chemistry I
Academic year:

2021
Views:

463

Pages:

2
Author:

Marilyn James

KEY Worksheet: Solution Stoichiometry 1. How many grams of lead (II) nitrate are needed to fully react 23.5 ml. of 0.55 M sodium chloride in the precipitation of lead (II) chloride? Pb(NO3)2+2NaCI PbCl2+ 2NaNO3 • 023521055001 / 1 mol Palade/331.2g = 2.1gPb (203) 2 ہو. I Liter Zood Null Imol Pb(NO3)2 Zmol NaCl 2. When 53 ml. of 0.75 M cobalt (III) nitrate are added to a sodium sulfate solution, how many grams of cobalt (III) sulfate can be precipitated? 2Co(NO3)3+3Na2SO4 Co2(SO4)3+6NaNO3 05311.75molds 40bly Coz (sav)3 1 Liter 2010(103) Inol Co₂(504)3 -= 18.1g Co₂(504) 31 3. How many grams of aluminum hydroxide will be neutralized by 45.3 ml. of 0.55 M HCI? 3HCI + Al(OH)3 AlCl3+3H2O 178g AlCalls = 10.648 10.55 Aul 1 mol H(OH)3 +8g 0453L/0.55 I Liter Bmol HCl / Imo/41(04)3 4. What mass of AgCl will precipitate when .050 L. of a 0.0500 M solution of AgNO3 reacts with 25.0 ml. of 0.0330 M NaCl? AgNO3(aq) + NaCl (aq) → NaNO3(aq) + AgCl (s) I Liter TimolAgios Imol mol/143.4919/0251.0330 mo 12g AgCl 5. 50.0 ml. of 0.100 M Na3PO4 is mixed with 150.0 ml. of 0.250 M Pb(NO3)2 to produce a solid precipitate of lead (II) phosphate. What mass of this precipitate will be produced? 3Pb(NO3)2 (aq) + 2Na3PO4 (aq) Pb3(PO4)2 (5)+6NaNO3 (aq) 05011.1mo Im 811.6 // Liter (2mol/lmo 150250001 mol Blliby 1Liter 3mol Imol = 2.03 Pb (P4) = 10.1g 0 6. What mass of solid aluminum hydroxide is produced when 50.0 mL of 0.200 M Al(NO3)3 is added to 200.0 mL of 0.100 M KOН? Al(NO3)3 (aq)+3KOH (aq) → Al(OH)3 (s) + 3KNO3 (aq) Liter laul 0.849 •0500 2004.100ml/1owl/8u4y = (0.56gH (04)3/Citer/3mol (Mol 0 7. What mass of barium sulfate is produced when 100.0 ml. of a 0.100 M solution of barium chloride is mixed with 100.0 ml. of a 0.100 M solution of iron (III) sulfate? 3BaCl2 (aq) + Fe2(SO4)3 (aq) → 3BaSO4 (s) + FeCl3 (aq) •100/1000/30011233.49 = 2.33 ghusky 1004/100ml/300/233.4 = 6.999 8. How many grams of silver chloride can be prepared by the reaction of 100.0 mL. of 0.20 M silver nitrate with 100.0 mL of 0.15 M calcium chloride? 2AgNO3 (aq) + CaCl2 (aq) → 2AgCl (s) + Ca(NO3)2 (aq) 100120ml/2mol/143.4g. 12mol/14349 = 202.99 Liter 2mol/mul 100/1500/200/143.49 = 4.3g liter Imol Imol