University:
Missouri State University
Course:
MTH 460 | College Geometry
Academic year:

2019
Views:

275

Pages:

2
Author:

lirmzinlelfuu5

Geometry -- Unit 8 Pythagorean Theorem Practice Name Date Find the values of all variables. Keep answers is simplest radical form! Show all work! 1. x = 2sqrt(5) 2. x = 12 y = 4sqrt(3) 3. x = 5sqrt(5) 10 62 x+ 36 = x ^ 2 + 16 2+42 sqrt(620) = boxed x 2sqrt(5) = x 11 13 ^ 2 = 5 ^ 2 + x ^ 2 169 = 25 + x ^ 2 32/144 + x ^ 2 -> 12 = x 20 y ^ 2 = 12 ^ 2 + 8 ^ 2 y ^ 2 = 144 + k ^ 4 7^ 2 = boxed 208 = 4sqrt(3) 15 15 ^ 2 = x ^ 2 + 10 ^ 2 sqrt 125 = boxed x ^ 2 225 = x ^ 2 + 100/15 5sqrt(5) = x 4. x = 9 * 12 15 12 15 ^ 2 = 12 ^ 2 + x ^ 2 * sqrt(81) = sqrt(x ^ 2) 225 = 144 + x ^ 2 9 = x 5. x = 38 cong triangle s 15 15 ^ 2 = 12 ^ 2 + y ^ 2 225 = 144 + y ^ 2 boxed 8 |= boxed y ^ 2 y=9 x = 9 + 20 + 9 x = 38 6. x = 10 x ^ 2 = 6 ^ 2 + 8 ^ 2 x ^ 2 = 36 + 64 boxed x ^ 2 = boxed 100 x = 10 5 Complete the following word problems. Make a drawing (there should be a right ). 7. A soccer field is a rectangle 90 meters wide and 120 meters long. The coach asks players to run from one corner to the corner diagonally across. If players must run corner to corner 5 times, how far do they run? 90 120 120 १० x ^ 2 = 90 ^ 2 + 120 ^ 2 x ^ 1 z^ 2 - = underline 8100+14400 boxed x ^ 2 = boxed 22500 x = 150 corner to corner 5 times. 150 * 5 = 750 The players run 750 m. 8. Jenny wants to put an underground sprinkler system in her back yard. A drawing of the system is shown below. How much piping is needed? x ^ 2 = 45 ^ 2 + 28 ^ 2 x ^ 2 = 2025 + 784 x ^ 2 = sqrt(2809) x = 53ft . 28 ft. PX 28 deg Pipe 45 ft. Piping needed = 28 + 45 + 53 = 126ft . 9. Firefighters have a 17-foot extension ladder. In order to reach 15 feet up a building, how far away from the building should the foot of the ladder be placed? 17 15 X 17 ^ 2 = x ^ 2 + 15 ^ 2 289 = x ^ 2 + 225 225/(sqrt(64)) = boxed x^ 2 The foot of the ladder should be placed 8ft. from the building. 8 = x 10. A rhombus has a perimeter of 60 inches. If one diagonal is 18 inches, find the length of the other diagonal. 225 = 81 + x ^ 2 15 ^ 2 = 9 ^ 2 + x ^ 2 boxed 44 = boxed x ^ 2 12 = x 15 60/4 = 15 15 15 15 The other diagonal is 24 inches. 11. Farmer Brown wants to put a fence around a triangular shaped field. A rectangular barn is directly next to the field. Farmer Brown is not going to put fencing along the side of the field that is right next to the barn, but will along the other two sides. The fencing will cost him $3.79 per foot. What will be the cost of the fencing? x ^ 2 = 30 ^ 2 + 72 ^ 2 x ^ 2 = 900 + 5184 sqrt(x ^ 2) = boxed 6084 x = 78 35 yd 30 yd BARN FIELD 35 72 yd Fencing g = 78 + 72 = 150yd Cost-450-3.79=$1705.50 150 * 3 = 450ft If a triangle is formed with the given lengths, is it a triangle? If so, what kind of triangle \mathbb{R} 12. 6, 7, 10 137100 13. 4,8, 4sqrt(3) \\ 16.3 matrix 4+413>8 Is it a Delta : YES NO If YES, what type: Equation: 10^ 2 100 ? (6 ^ 2 + 7 ^ 2)/85 acute right Is it a Delta YES NO If YES, what type: Equation: (8 ^ 2)/64 = (4 ^ 2 + (4sqrt(3)) ^ 2)/64 acute right obtuse obtuse 14. 4,9,5 15. 2,4,9 (8.49) 621479 Is it a Delta : YES NO If YES, what type: Equation: ? acute right obtuse Is it a YES NO triangle i If YES, what Equation: (9 ^ 3)/81 > (4 ^ 2 + (6sqrt(2)) ^ 2)/88 acute right obtuse