Stoichiometry Worksheet and Key

Stoichiometry Worksheet and Key lameeya 1st pd 2 KCIO, 2 KCI 30% 1. How many moles of O, will be formed from 1.65 moles of KCIO 1.65 mol KCIO, mol O - 2 mol O 2 mol KCIO, 2. How many moles of KCIO, are needed to make 3.50 moles of KCT 3.50mol KCI 2 mol kcio 2 mol και 225 mol KCIO 3. How many moles of KCI will be formed from 2.73 moles of KCIO. 2.73 moks 2 mol και 2 mol KC10 = 8.73 mol KCI 4Fe + 3O_{2} -> 2F*e_{2}*O_{3} 4. How many moles of FeO, are produced when 0.275 moles of Fe is reacted? 0275 mol Fe| 2molE*e_{2}*Os 44 m Ol Ee |= 0.126 mol Fe 2 O 3 5. reacted? 31.0 mol.02/2 2 mol Fe 3 mol 02 20.7 moi FC 6. How many moles of O_{2}*j are needed to react with 8.9 moles of Fe? 8.9molFe |3 mol 02 4 mot FC |= underline 6.7 mok 02 2H_{2}*O -> 2H_{2} + O_{2} 7. How many moles of O_{2} are produced when 1.26 moles of H_{2}*O is reacted? 126 mol H20 I mol = 6.30 mol 2 mol 8. How many moles of H_{2}*O are needed to produce 55.7 moles of H_{2} ? 55.4 mol Ha 2 mol H20 2 mol H20 = 55.7 mol H20 9. If enough H_{2}*O is reacted to produce 3.40 moles of H_{2} then how may moles of O_{2}*T must have been made? (a bit challenging, but just think about it and you can probably figure it out) 340 mol imol 02 = 1.70 mo 2 mol 2 KCIO, 2 KCI+ 30, + 10. How many grams of O, will be formed from 3.76 grams of KEIO, 3.76g KCIO, 1 mol KCIO, 2 molo 122.55 KCIO, 2 mol KCIO, mol Os 11. How many grams of KCIO, are nooded to make 30.0 grams of KCI? 30.0 KCI mol KCI 2 mol KCIO 132RCIO 2 mol KCI 12. How many grams of KCI will be formed from 2.73 g of KCIO 2.73 KCIO mol 42.7 g Fe mol KCIO, 49.3 KCIO, 2 mol και mol KCl/ 74.5591 122-55g/2 1 mol και 4068 KG 1 mol Fe 55.85g Fe 4Fe + 3O_{1} -> 2F*e_{2}*O_{3} 13. How many grams of FeO, are produced when 42.7 grams of Fe is reacted! 2 mol P*e_{2}*O_{1} 690, 4 mol Fe mol Fe 0, 14. How many grams of FeO, are produced when 17.0 grams of O_{2} is reacted? 17.0 g 0 2 mol Fe 159.709 Imol02 3 mol 15. How many grams of O, are needed to react with 125 grams of Fe? I mol- 13200912 Some cars can use butane (C_{4}*H_{10}) fuel: Ex6.50 B FeO, 2C_{4}*H_{10} + 13O_{2} -> 8C*O_{2} + 10H_{2}*O 16. How many grams of C*O_{2} are produced from the combustion of 100. grams of butane? 100. g C₄H₁/Imo cut$8 . 8 mol 144.019/. mol 58.149 17. How many grams of O_{2} are needed to react with of 100. grams of butane? 100. g 12 C.Homol C4H1013 mol = 303 800, /1mol 158.149 32.002/. 1 mol 02 2 mol 368802 18 How many grams of H_{2}*O are produced when 5.38g of O_{2} is reacted? 5.38g/1mol02 110 mol H20 13 mol O2 13 /18.029 I mol 32.009 =( 2.33gH * 2O 125g|(1molFe)/(55.85g)| * 3/(4mol) | matrix 3200g 1mol |* underline 53.7g0z