Properties of Helical Path - Edubirdie

University:
Santa Fe College
Course:
ETS 2527C | Electromechanical Components and Mechanisms
Academic year:

2024
Views:

472

Pages:

4
Author:

Jabin F.

Properties of Helical path => radius: mv²/r = qvB ⇒ r = mv/(2B) if B = non-uniform = Bozz^ BB > BA BA ≠ BB γA > γB radius decreasing Time period T = 2πr/v⊥ Pitch of Helical Path P = Tv|| P = (2πr/v⊥)v|| V|| = V₀cosθ V⊥ = Vsine P = (2πTr/Vsine)V₀cosθ P = 2πTr cotθ ⇒ P = Tv|| P = V||(2πm/2B) r1 = a, r2 = 2a, r3 = 3r2 = (3x2)a = 3!a B1 = μ₀I/(2a) B2 = μ₀I/(2(2!)a) B3 = μ₀I/(2(3!)a) Bnet = B1 + B2 + B3 + ... = μ₀I/(2a)[1/1! + 1/2! + 1/3! + ...] ... ex = 1 + x/1! + x²/2! + x³/3! + ... ⇒ e^1 = 1 + 1/1! + 1/2! + 1/3! + ... from (i) Bnet = μ₀I/(2a)(e-1) Q(4).20 Page-42 I = λvR B = μ₀I/(2R) B = μ₀(λvR)/(2R) B = μ₀λv/(2) B = (μ₀λω)/(2) (option-b) Prob. opposite → I I = e/T = ev₀/(2πa₀) B = μ₀I/(2a₀) B = (μ₀ev₀)/(4πa₀²) into the page.

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