University:
Swansea University
Course:
EG-086 | Engineering Science
Academic year:

2023
Views:

167

Pages:

3
Author:

J. Tomson

20/10/2017 Friday mp Energy Equador Glory to God" ay to Giard deoive RTT tiny drake $1 =Susdr+ CV N-E n=e lesat + festion. de- & lescht at 2 Q-W= Sesat + festida dt Wshear + W nemel + Wother i = kishaft + Wcher = ی Wnormal = - Sorn . di σ - xx = -P 544737-865 Pagra 9.08 + PỪ. dÃ .. Winormal Substituting Substituting Sesd++ Q-Womy Sesat + fest.dh (4) + Sp.dd- (Asamin Wiener = Woller =) Rewriting, How? Q-wishaft = of Sesat + Sept. da + Jorda -wishaft = &fesd++ Je+ pulst.dr- di (5 e = u + x + gr 2 Rewnting, -Wishoft (u+v+ ut 2 + CH198+P) 2 Q-wishogt & S(4+x+93) a 2 + Ard Q. Air @ 101325 pa and 22°c enterne a compressore wils negligible velocity" Ond 344737865 Pa, is d@ discharged 36 C Herough a witb o. Im² area. the flow rate is the power input to the Complector is 44720 w pipe 9.08 Kals Determine the rate of heat transfer. Assumption stody flow Idad No gas No potential radifferm (S₁=BL) inlet velocity is almost -visnet = ((h+++ 98) 5. d thors 102-5105 = - 2 22 SLAZ (hi+v+gi)SVIA+ (h₂+ +930) Q= Wang + mi (ha-hit - 19(3075) 2 2 2 Q = Wangt + ni(An+½²) Q = Wangt + nmAh) +rm² 2 Q = INsway + ni(CPAT) + m 2 2 LA2V2 = S, AV, (i also BRT Rais = 287- $2344737-865 267×38+243) 3-8623 9.08 31.609 x 0.1 x2 9.08 - 23.5 m/s 3.8623 2 = -44720 +9.08 (1000x (38-22)) +9.08×(23.5) 2 Q= 103067.215 J/s Q-103.1 KD