University:
The Pennsylvania State University
Course:
CHE 220 | Introduction to Chemical Engineering Thermodynamics
Academic year:

2020
Views:

156

Pages:

17
Author:

study_genius

Agenda Working aith the * Interpolation * Examples Reading : Section For Today team 22 Tables ExAMPEttliAtanKmthVtE2m3containsM-4kgofst.eqme@IZ4bar.W hatisthephaseand temperature solution Weknon : ¥38 Yf V=Vt¥= : -- os V=o5YIg ;R4bar : Interpolation : -4=1504--0.4709 tz Vz -0.5343 -200 t.tn#t(v.v.1= Vz - Vi Interpolation near 172.9°C y. ¥ = -* - - • - - - - - 1 1 ' 1 1 ) ' Y= Yit ' '' Xz ' - ' " Xl ( x . x , ) Examputcont 'd : lfthemassinthepveviouspartismelokg andtemperatui phase Solution what is the , . : F- 4bar ,TsM= V= kverpuk : XL : ✓ • • 0.00108 02 • 0.4624 -06*2=0.569 0.4624 ANSWER 143.61% 3%3=0 .zmIg - 0.00108 V1Lmixthe@PttbasT-143.6l0Shith56.91.L No# Wetsteam Quality Moisture -743.1% -756.9% .IQ . Example I , cont water . mass The 'd : If the volume fraction of the liquid and mass ¢ 4bar the rd . total fathom temminhmrixxinhtxwixiiifa XL = QVV = law to - VIL a 25 't , in the mass tank : snetrx : Vol Mass : V= . w 0.993 m= xiltxvvv ÷ = = MYKG 0.00429 ¥ my 00429 = kg mixture determine ADK Specific Total contains of the liquid is fraction Relationship btw Solution ; tank @ same 466.2kg . of the EXAMPKZ 160L A ; tank contains t34kgofwater@25ooC.W hat is the phase and pressure ? Solution V= pk 0*6,3=0.1/94 18 bar Pz=z0 Exercise : Repeat V, = Vz= Yfg 0.1115 0.1255 withmkkg MYKG We Know V ,T P tsinterpdatimnpflalbar Exampk3.iDetermihethephaseandspeaficvdumeofwater@80440bars.w ' .in#rummsevi9md jail !µ assumepvjsothermisrericd V@80°C , 40bar .tl#h0oC=0.474= " Exampk4iSpeaifcvo1.ofsteam@2Z3oC.b -75bar Double f- Interpolation a- a)( 1 -b)f : " tbaohfiztaa - bfz fiz •f fzz •fz÷ Yz , • . Y, tabfzz " - • z V= 0.329M¥ g Tbar •03 6.5bar Yt Y, • - • 0.3241 = 200°C • 0.3364 0.362g z 250°C Exampk5i.AC1osedtank@1barcontainsWetSteamWithquality2oj.HeatisaddednntilT-l2ooc.WhatispandthenewqualityaCfina1state.SdutionafTi-99.630CVL-o.0olo4P-lbarVv-1.6q4XV-0.3396m38Xv-O.zwn.fKitgleFEi2a0kbarVvEoooo0aY5-xr.o.aa , V= 0.3396 Kunst Exercise : 0.38 4 .V process XVI morevapor ' Mouheatisaddeduntiecontentsbeamesatkp mhatistandp ? . NIST Webbook c- click here E choose Your units Choose of Ctry type data other choices ) choose c- click to continue range to view data in tabular data in graphical t form form Properties of sat . Example -1=1000 ( PSAE 't : VL -0142kt Properties of . Jat . ✓