University:
University of Alberta
Course:
OM 252 | Operations Management
Academic year:

2024
Views:

260

Pages:

2
Author:

MICHELLE SIACA

Problem 6-16 (Static) 50/50 points awarded Scored Develop a process layout that will minimize the total distance traveled by patients at a medical clinic, using the following infon projected departmental visits by patients and distance between locations. Assumea distance of 35 feet between the recarea and each potential location. Use the format shown. DISTANCE BETWEEN LOCATIONS (feet) From To A B C D E F A 40 80 100 120 160 В 40 60 80 120 C 28 40 80 20 40 40 eBook Print D E F TRIPS BETWEEN DEPARTMENTS (per day) To Reception 1 2 3 4 5 6 References Reception 20 50 210 28 10 130 1 10 40 110 80 50 2 40 50 40 120 3 4 10 10 250 10 0 40 90 5 6 10 20 30 Click here for the Excel Data File A F Reception B E C D Location Department A 3 B 5 C 1 D 4 E 6 F 2 Explanation Given: Distance between the reception area and each potential location (A, B, C, D, E, & F) = 35 feet. The reception area must remaln in the central location; therefore, we can omit the reception area from our analysis. First, we will list the department pairs and the number of trips between them. Number of Trips Between Order of Assignment 1-2 0 10 1-3 40 7 (tied) 1-4 110 3 1-5 80 5 1-6 50 6 (tied) 2-3 0 10 (tied) 2-4 50 6 (tied) 2-5 40 7 (tied) 2-6 120 2 3-4 10 9 (tied) 3-5 250 1 3-6 10 9 (tied) 4-5 40 7 (tied) 4-6 90 4 5-6 20 8 Second, we will assign departments based on ranking the number of trips between departments. A reasonable set of assignments Is: 3-A, 5-B, 1-C, 4-D, 6-E, 2-F. The distance (In feet) between departments Is shown below: From To 1 2 3 4 5 6 1 80 80 20 40 40 2 160 40 120 40 3 100 40 120 4 60 20 5 80 6 Then, for each department palr, we must multiply Number of Trips Distance. Number of Trips Distance From TO 1 2 3 4 5 1 0 3200 2200 3200 2000 2 e 2000 4800 4800 3 1000 10000 1200 4 5 2400 1800 1600 6 Total distance traveled per day = 40,200 feet.