University:
University of Arizona
Course:
CHEM 141 | General Chemistry Lecture I
Academic year:

2017
Views:

138

Pages:

1
Author:

CloudMaster

This exercise is to predict a metathesis reaction. First of all, we need to predict the identity of the precipitate that forms. An aqueous solution of ferric chloride and potassium sulfate are mixed, and then we are able to write the reaction balance the equation. So, we are given two ionic reactants and asked to predict the solid products that they form. The LaPlante method tells us that we need to write the ions present in the reactants and exchange the anions between the two cations. Once we have written the chemical formulas for this product, then we can use the table for point one to balance the equation. Determine which is insoluble in water, knowing that the products will also allow us to write the equation for the reaction. So, here we have these two reactants and we need to separate, we need to dissociate both of them. These are soluble ionic compounds and they will produce four different ions. First, remember that this verse is a Caution: This one is an anion. This is a cation. This is a cation. This is a visit. The one that is an anion for this second reactant. So, we need to interchange this cation with this anion, and this cation will visit iron to create your product. So, the reactants we have here: - Barium with a +2- Iron with a -1- Chloride- Potassium with a +1- Sulfate with a -1 two. That's why we have two potassiums here. So, as I mentioned before, we can combine these two ions - potassium chloride and barium sulfate - to create the two products. Now, that we have this, we can check the solubility table to see if any of them are insoluble. The table mentions that all of the sulfates are soluble. Insoluble, but with this exception, we have barium. Barium sulfate is going to be a solid and, unlike potassium chloride, it is insoluble. However, all the chloride in potassium chloride will be soluble, with the exception of silver, mercury, and lead. So, potassium chloride is soluble. Therefore, the final reaction will be barium chloride. aqueous solution. It is soluble in potassium sulfate, and also remember that sulfates are generally soluble except for certain cations. As you can see here, it forms soluble compounds with chloride, with the exception of three cations. Barium is not one of those cations, which is why both of them are aqueous in the reactants and will produce environment sulfite is solid and potassium chloride will also be a solid solution.