Dimensional Analysis - Molarity as a Conversion Factor | University of Arkansas - Edubirdie

University:
University of Arkansas
Course:
CHEM 1123 | University Chemistry II
Academic year:

2019
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204

Pages:

1
Author:

BobN

In this example problem, we use molarity as a conversion factor in dimensional analysis. Our problem reads, "What mass of nitrogen in milligrams is contained in 12 milliliters of 0.25 molar magnesium nitrate?" When we're given the molarity of the solution, 0.25 molar magnesium nitrate means 0.25 moles of magnesium nitrate per liter of solution. Since this is a ratio of units, we can use it as a conversion factor, just as we would density. From our molarity, we know 0.25 moles of magnesium nitrate equals one liter of magnesium nitrate solution. The only other number we're given in the problem is our volume of solution, so we'll start our dimensional analysis with 12 mL of magnesium nitrate solution. We'll need to convert our units to milligrams of nitrogen. Using the definition of milli, we can convert from milliliters to liters of solution: 1 milliliter equals 10 to the negative third liters. Using our molarity, we can convert from liters of solution to moles of magnesium nitrate. Next, we'll use our chemical formula to convert from moles of magnesium nitrate to moles of just nitrogen. Each mole of magnesium nitrate has two moles of nitrogen. Next, we can use the molar mass of nitrogen to convert from moles of nitrogen to grams of nitrogen. Our last step is to use the definition of milli again to convert from grams of nitrogen to milligrams of nitrogen. Completing the calculation, we get 84.1 milligrams of nitrogen.

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