Leave the text unchanged, do not delete or add anything, just correct typos, punctuation, and paragraphing! Use [English] and use Markdown for formatting. In this example problem, we look at thermal energy transfer between a metal and water. Our problem reads: "A 15 gram block of aluminum metal, originally at 98 degrees Celsius, is dropped into 55 grams of water, originally at 25 degrees Celsius. If the specific heat of water and aluminum are 4.18 joules per gram degree Celsius and 0.903 joules per gram degree Celsius, respectively, calculate the final temperature of the metal and water." In this problem, because we're dropping the metal into the water, we know all of the energy that's lost by the metal will be transferred to the water. So, the heat for the water is equal to the negative heat for the metal. Our equation for Q for the water is: Qw = (mass of the water) * (specific heat of the water) * (change in temperature for the water) The mass of our water is 55 grams, its specific heat is 4.18 joules per gram degree Celsius, and its change in temperature is the final temperature (which is what we're trying to find) minus 25 degrees Celsius. For the metal: Qm = (mass of the metal) * (specific heat of the metal) * (change in temperature for the metal) For the metal, that's 15 grams * 0.903 joules per gram degree Celsius * (final temperature minus the initial temperature, which is 98 degrees Celsius) Now, we just need to plug Qw and Qm into our equation and solve for the final temperature. Qw is on the left and Qm is on the right, and we need to multiply Qm by -1. We can distribute 55 * 4.18 * (TF - 25) on the left and -15 grams * 0.903 * (TF - 98) on the right. Then, we need to get all of our TFs on one side and our numbers on the other. So, we'll add 1345.0F to both sides and add 5747.5 to both sides. Then we can solve for TF by dividing both sides by 29.9 + 13.545. If you put this into your calculator, you should get 29.06 degrees Celsius as the final temperature.