University:
University of Central Florida
Course:
MAC 2312 | Calculus with Analytic Geometry II
Academic year:

2023
Views:

276

Pages:

9
Author:

Maria

Q1 J -6) : Sudu - 6x + 7)"dx (n + c = 2 5 9-20 x Q2 : +) 5 6x - ox5 dx u + =Grudu=julz du Q3 : 7 + du=-6dx 5 2 = 6x - u = /(3x- 6)dx ↓ j3(3x-6)"dx 10 x - du == 2 ju = u du = = 7)5 + + 3x = + 20x + c - 6 2 2 C 8 dx z(-10x = + 8) 2 + c 3dx 7 gubdu= = . +u + c 7 3 + (3x 6) + - + c 21 Q4 : fx(x - 4)8dx u = X - 4 - x = x + 4 du=1dx Su 4/a"du=Sus + +4u8dn : "not 18 = + (x - u y) + C (x + - 10 Q5 : /cos" (3x)sin (3x)dx u = cos(3x) du=-3sin(3x)dx 19320(3x) sin (3x)dx= Jude = 1+ - osx) =I . (bx =os 439 + e Q6 : - - ((5-15x4cs(x3 59(1 + 3x4)as(x3 5/csn du - = = : dx 6x : + (3(4x x 3x" 1 - + + C 5ct(u) = + x + 6x5dx 6(13x = 3 2(x2 + 8) + c xY(3x" + x38dxu 3x + x = du = 12x + xx(3x" + x3)8dx = 3 + 3x2dx 3(4x3 + duu+c=xes x4)dx e 27 n = + x5)dx +c 3 du = 2xdx + C c = = ((4x* + x) - -St=fuzu Q9 : - x)dx du = 48 x =du Q8 - 5 20t(x3 u = X = du = 5(-cot(u)) : Q7 x)dxn - xi + 3 du = 4x3dx Ja=fudu=c = + C 2 Q24 : jux2dx 3x3 u= du = gx = z - " dx du=ndu= => sa = u = du 2x3 + 4 * = 6x dx ↓ 3 ( us I = Q26 : Stan'(see(x>dx n = -"de S 2 = (43 - - 2 3) tan(x) du=see"(x)dy = 5 gudu - 1 F = 51 E Y (1)" = ↑ xtan" (3x4) see(3xdx Sextace 5 - 3 -" = * u = tan (3x ) du =sect(3x4(6x)dx a = 5 udu= = 0 ((r)5 1) -