Adjoint of Matrix Lecture

University:
University of Michigan
Course:
STATS 125 | Statistics, Games and Coincidences
Academic year:

2022
Views:

263

Pages:

4
Author:

AuroraAvenger

* Adjoint of matrix: & A=1 20 -13 -256 Find adjoint A. A=+34+(18-20) = -2 A12-14-(-6+8)=-2 -26 A13= +-13=+(-5+6) = -25 An-128=-(12-0) = -13 12 56 A22=+128=+(6-0)=6 A23-12-(5+4)=-9 -25 A=+20+(8-0) = 8 34 A32-1101=-(4-0)= -4 14 A33=+12=+(3+2) = 5 -13 R Find adjoint of matix: 2 -13 4 -256 ⇒ A=+/38=+(18-20)=-2 A12-1-14-(-6+8) -26 -2 A13=+1-13)=+(-5+6) = 1 -25 Ax=-120-12-0) = 56 1-12 Az2=+110+(6-0) = 6 -261 A23=-122=-(5+4)=3 A31 = + 120=+(8-0) 34 8 A32=-1101=-(4-0) = (-4 114 A33=+12=+(3+2)=5 -13 Cofactor matrix = C = -2-27 -12 6-9 8-45 adj A = CT = -2-128 -26-4 1-95 * find adjoint of matrix: 2 A 34 ⇒ All +4 adjA= 4-2 -31 A12-3 A21-2 A22 = +1 Cofactor matrix = C = 4-3 -21 T adj A = c = 4-2 -31 * B = [] adj B=3 527 5 * C= [2] adj C = R و 0 2 -* A= 47 adj A= -8-3 * -2-1 0 3 ⇒ adj A=3-2 31 * B=5-2 adj B = 3-4 -35