University:
University of Waterloo
Course:
PHYS 111 | Physics 1
Academic year:

2023
Views:

89

Pages:

2
Author:

niyunong108

stopping timesutoV=0toP.WV=u+ab(NM)to7C0=u+c-a)famDCo=u-abab =4the m magnitude or rebardation6=4/2a is 1xm = >f =mu>PmmaFt= PFK.E = p2 anp=2mckE)to =2m CKE)F2 The car and a beuck moving with a same momenteenwhich will stop Sast, are same ->the breaking forces are sameb=p/Fsince pand F all some the to all same?The cas and a beuck are moving with a same Kinetic sameenergy which will stop sast The breaking forces aret=2mCKE)Fiscarsince K.E and F are same 6 Im thator