Magnetic Circuit Questions and Answers

University:
Washington State University
Course:
Physics 101 | General Physics
Academic year:

2021
Views:

315

Pages:

10
Author:

Janor

Magnetic asuite2 = N2 d 012 = N2 d 012 di,Q21= K2 122 -3111: putdtdt diV@&leakageflexusefulflune2 = Middi,magneturing fluxdtQ12 = K, 014M12 = N2 do12-1L= N doordi,dt2e, = M21 dizM2, = N, dQ21dtdizMultiply1X2M12 x M21 = Nzd012 X N, d 021di,dizuse 3 & 4 eq" M2,XM12 = K, k2 N1 ,do, x N2 dq2= K, K2 L, L2di,If M21 =M12 =M & KI=K2 =kdizM2 = K2LIL2M=K L1L2 K = coefficient of couplingK= usyful fluidTotal flexIt depends an (ii) orientation of coil(ii) Core material(iii) Self inductance.It doesn't depends an the No. of turns anthe coils.osksl Dot polarityQ12iseeziMiz421,current entering the dot b12L2a4inducingpolosity0ani,i2coil.c4L2MdizMdi,dfdt i2@2i2i2ai2cL24bMdi2Mdi,Itdtsisi,a3Q2cMdiz-Mdi6FItdt KMyQEquivalent inductance b/w a sb a L, L2Sal=L2 Mdidt-+4MdiMdiMdi4L2draoyVab = Lidi + L2 di - 2MdibadtdtdtVaf= Leq di Leg (4+22-2M)It 01/11/19 -4++2 +2Mof of4 + + 2 - 2MQL1+L2 2M.aallaLeq = LIL2-M24L2L,+L2+2M asI-P,=12I-1,IVLeg-412 - M25BL22.MdI-IKLCL1+12+2MIMdi,dtdtShziz-Msi, + Msiz - Lsil =0i2=4+MI = i,+i2 I= ii+(L,++ 22+M )i, = i(( L2+M+LITH) L2FM f =V= leqsIL2+MV= Leq S L2+M i = usi, - Msiz= leg [ L1+ L2 +2M b2M jie = 4si,- M [ L1+14 L2+M I'i4- - M(L1+M )4,22+4M-L,M-M2Leg =L2+M=L2+M=4+L2 + 2ML,+L2+2ML2+ML2+M leg= = L,L2 - M21,24+2,-2M43-M-312Leg=LIL2-M243 My 3122,+1,2 MI1052j3 52=Find 'k' for-j37-2kj2752Series resonanceoAns K= 0.4 solI,MSM=)I24L21/2S413ItI2tS4SL2vi = S4I, + SMI2v2=)vSMI2SMI,V2 = SM I, + SL2I2[2] = 21 in M in]4-M L2-M#-M+MMML2-M+M]= [z]M4,+ML2tMHor00[2]=L1+M-M-M-M- ML2+M-M O'l [2]=? of the ckt" MyMILLLI.sol52SLSLStSLv,= s[32-2M]I, - + SM I2SMI,SMI,SMI,SMI2V2 = SM I, + SLI232-2M -MZ =OMLMonk