Electric Potential Energy

Electric potential Energy The energy related · field depending · Similar w) the to to its on the q Q# uniform created a) decrease is direction is (16 X10" ) ( (S0) (1 = 2 4 . proton negative charge to the Q #2 plate will X the as 1 Om away from . a) (v) relative to a) = qEy = field of magnitude has a lines 1 0 m relative to from plates released ? does . /U) the plate increase or 0) , in will it . - uniform a electric 2 . 4 x field of ISONIC , or decrease ? (150) (1 0) . 10. j move upward move closer ↳ the (U) will lower ? (v) increase move negative charge will is ISONIC plate ? b) electron will plate field = plate because of the plate and the potential energy will lower electric field lines are moving further apart 1 6 X10"4) = field ~Ep mgy of charge plate b) What direction U . related downward towards the electron is located a the electric J 10- move the on in energy gravitational plate electric released ? once = b) the to potential energy of proton when electric gEy = uniform a due the . what U field in where the by negatively charged plate Proton b) what a) electric located in location qE y = location its position due to its is mass proton due to gravitational potential energy u : charge particle as it , away the (U) from will the plate increase of as the x gets further from the plate the electric Another electric U 1, U2 field is Vi + Exel electric : Uzt Elez = potential energy Ele , Ely Kinetic energy = Q# electron starts plate . what electric uniform is the speed of = v = q = -DER at 5 2 cm or field magnitude before it a the electron LU 220N/C OS2M .4 1 6 x 10 0 electron 4 11 A10 = : " . Reg = = (0) - 1 . 220 NIC is of > - ( - . P) /220) 70 0S2) 6 x 10 . 10"0 0304 x SAMPLEQ# O positively charged plate produces 1 3 . X/03 NIC . Electron from rest 1 2 X 10 at position is the speed as the Yo position if hits the = = 10) . x 2 446 X10 = 10" - 18 . ·Ex = OEK = OEK vq /- 1 6 - = = . 2 . I mu ju 2 26 2 = %8 : . 446x10-8) 4 /1 X10 - 31 . = 2 34/X10 . = = " mrs - OU - 1 . & 8304 X 10. < mu 18j 2 What plate ? is when the 3 x 10") / 1 2 x 10 J 446x10 = vg . m) 2(1 8304x10 = - . & = - OU - . DEL is . plate gEy-gEY9) (1 - = that 0 as electron hits the ou that away from plate m . a En OEK released is . plate. hits the Up-Vi formed g Y GE Yi C . of = = . mass from positively charged . be O plate & - E rest from A Let the of energywi uniform conservation of approaching way 2 . 00 x - (1 X/0 10 ° - 18) 3) m/S Electric potential (v) Charge q is placed in · electric which potential v , the Vigu be can is larger energy Electric · position · , the · when · X The /q of charge electric potential is to as voltage something between where U positive higher lower to some it describes the and the terminal terminal , the the potential reference other potential electric potential is voltage terminal called is the terminal · potential difference Because v = the relative to this also / the larger relative always , one terminal the , voltage has voltage battery the amount is difference be location a potential energy of has charge potential energy Reffered at rearranged for VI The field electric an gEy is that , always meany will called negative considered absolute value - U = EY as U = qV , ON = you #1 positive and negative charged plate are positioned 1 1 cm 6-0 V . The potential difference between the 2 apart . are a) b) what is the electric if proton when speed V= 6 y = . 0 starts field ? from positive plate at rest half way across conservation what is of energy ? V 0 011 m mass luse , . of proton =? 67 X10-leg al E = Ey = V/Y = 6 0/0 011 = 545 NIC . . up - proton from positive plate will go up b) conservation V = -OU = 1 1 6 X10- = . 4 8 = 10 - 4) [ BV) 14 VI - 2 . 1 2 4 = . Vis6U, /1 6 x 10 x 10 6 7 X 10 . point 9) ( 3) v the the because they 30 is reffering are point of =, mu Ele ↓ x . total 9 The -qGV = OEM energy Gou OEM OEM of to the half way the total If plates v total for the half . 3U is - : 2 "m/S SAMPLE# a) electric potential position potential energy of proton b) Same · for = OE p · = X10" . = Ov X . 0') . how much linetic energy The from -OU 4 8 = . 4 0 = . -gOV potential difference/voltage = x 10. What is the electric ? (1 6 ") (3 0 UIqU b) 1 6 X 10" P) 13 0 X10) qu potential differerence = . e electron a) U 3 0 is X . a X10" 4 J 10" J charge (g) can obtain = A to B = . (DU) is also related to the Electric Current charges Current · Rate at which charge moves I · Measured The (OV) R · : in Amperes relationship and the resulting of Ohms of 2 = location to one another Oq/0 + between the the resistance unit = from potential Current (I) is : difference between 1 the : QV/R material between 12 = / VIA 2 OHM'S LAW or LV : 2 locations /R locations SAMPLEQ# what and potential is current a of 0 . difference across 12A , what is the LV = OV = = of a 150 -2 potential difference ? the ends resistor /R (0 12) (150) . 18V # electric difference a) is b) difference resulting the is current time ? b) I = -q = = current due to a potential current 80mV is established through (ms = 0 0 X10-3 = 6 4 x . . , the cell now 12 . many ? across cell, what resistance electrons = move 12 . S X 10 " & during that 5x10" 10- 6 A = (0 +) (6 6 4 . 4 as Cq/ot 2 = = n = of flows for OV/R = travel cell nerve membrane across potential a) I in Signals 6 x . . 4X(0)((X10") 4 x10-"C 10' "/ 1 X10' . 6 (there X 10-14 electrons are 1 . 6 X10" "electrons per a