University:
Acadia University
Course:
PHYS 1013 | Introductory Physics 1
Academic year:

2023
Views:

98

Pages:

2
Author:

Jumana Moidheen

is displacement x -dimensionally = a+66+cb² 28 correct. displacement and to is bime sind dimensions USE og A, B, C and also sind dimensions of Ac & 61 Amsa x = a + 6 6 + C62 катхо ac & b/c [a) = [x] (6)=6] [2]= (0] 3)(0-2) CC+9) = E (6)=250) [290]= (99) = (b] = (x) [66] = (2x) 1 = x 5 = dw 6 x T = L C = x C = L LT-2 C ac =PX-20) το στουπλάθετος από Νουλος =L2T-2 6/c = KT-X T SXCE dotu = v V = 9/6 +663 ? (p+q)CV-6)=nRY find al nos P=ML-1T-2 P+3 ✓ = velocity b=bime as 6 dimension 2 % = ^ = 9% ECAD=D a=b XT 9/=LT-1 = LT a=LT-1XT 663 = V 7= 6=63 6=LT4-3 = LT-EP P3 ? F = ax +66 + ct2 F = ax-displacement. a = Fox a = MHT-2 = MT-2 1=99 6=F/ =MLT-2+16 =MLT-3 cb² = F = 1/12 MLT-2+2 MLT 3P = a = MLT-2 46-9 =Rv2 =ML-T 2 a=m97-2 T-ML-1T-215 6-7-1 6=L3 MLST-2 २ 2 Displacemanb bime x=Asin (B6+cx) Sind dimension of 7=1×1 EM BG=COC = 1 B67 B=T-1 AB=LXT LRT

Displacement Question

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