Measurement Error & Experiment Exercise # 2

MEASUREMENT ERROR & EXPERIMENT Exercise # 2 1. (A) + 8% (C) 3% (D) 7% (B) 0.8 % L T2 (C) 1.8 % (D) 8 % ), error in measurement of L is + 2% and error in measurement of T is + 3%. The error (B) + 6% (C) + 3% (D) + 5% (B) 32 ± 0.8 W (C) 32 ± 0.2 W (D) 32 ± 0.5 W (B) 44.0 kg (C) 44 kg (D) 44.00 kg (B) 10 % (C) 15 % (D) 20 % The pitch of a screw gauge is 0.5 mm and there are 100 divisions on it circular scale. The instrument reads +2 circular scale divisions when nothing is put in-between its jaws. In measuring the diameter of a wire, there are 8 divisions on the main scale and 83rd circular scale division coincides with the reference line. Then the diameter of the wire is (A) 4.05 mm 10. (B) 5% The dimensions of a rectangular block measured with a vernier callipers having least count of 0.1 mm is 5 mm × 10 mm × 5 mm. The maximum percentage error in measurement of volume of the block is (A) 5 % 9. (D) Zero The mass of a ball is 1.76 kg. The mass of 25 such balls is (A) 0.44 × 103 kg 8. (C) + 0.3 cm2 Two resistors R1 (24 ± 0.5) W and R2 (8 ± 0.3) W are joined in series. The equivalent resistance is (A)32 ± 0.33 W 7. (B) + 0.1 cm2 To estimate ‘g’ (from g = 4p2 in estimated ‘g’ will be - 6. (D) Zero The least count of a stop watch is 0.2 second. The time of 20 oscillations of a pendulum is measured to be 25 seconds. The percentage error in the time period is (A) 16% 5. (C) + 0.03 cm2 For a cubical block, error in measurement of sides is + 1% and error in measurement of mass is + 2%, then maximum possible error in density is (A) 1% 4. (B) + 0.01 cm2 The length of a rectangular plate is measured by a meter scale and is found to be 10.0 cm. Its width is measured by vernier callipers as 1.00 cm. The least count of the meter scale and vernier callipers are 0.1 cm and 0.01 cm respectively (Obviously). Maximum permissible error in area measurement is (A) + 0.2 cm2 3. [Multiple Correct Choice Type Questions] In the previous question, minimum possible error in area measurement can be (A) + 0.02 cm2 2. Part # I (B) 4.405 mm (C) 3.05 mm (D) 1.25 mm In the Searle's experiment, after every step of loading, why should we wait for two minutes before taking the readings? (More than one correct) (A) So that the wire can have its desired change in length (B) So that the wire an attain room temperature (C) So that vertical oscillations can get subsided (D) So that the wire has no change in its radius 11. The pitch of a screw gauge is 1 mm and there are 50 divisions on its circular scale. When the two jaws of the screw gauge are in contact with each other, the zero of the circular scale lies 6 division below the line of graduation. When a wire is placed between the jaws, 3 main scale divisions are clearly visible while 31st division on the circular scale coincide with the reference line. The diameter of the wire is : (A) 3.62 mm (B) 3.50 mm (C) 3.5 mm (D) 3.74 mm 12. The smallest division on the main scale of a vernier callipers is 1 mm, and 10 vernier divisions coincide with 9 main scale divisions. While measuring the diameter of a sphere, the zero mark of the vernier scale lies between 20 and 21 mm and the fifth division of the vernier scale coincide with a main scale division. Then diameter of the sphere is (A) 20.5 mm (B) 21.5 mm (C) 21.50 mm (D) 20.50 mm [Assertion & Reason Type Questions] Part # II In each of the following questions, a statement of Assertion (A) is given followed by a corresponding statement of Reason (R) just below it . Of the statements mark the correct answer as (A) Statement–1 is True, Statement–2 is True ; Statement–2 is a correct explanation for Statement–1 (B) Statement–1 is True, Statement–2 is True ; Statement–2 is NOT a correct explanation for Statement–1 (C) Statement–1 is True, Statement–2 is False. (D) Statement–1 is False, Statement–2 is True. 1. Statement I : If the error in measurement of mass is 2 % and that in measurement of velocity is 5 %, then the error in measurement of kinetic energy is 6 %. Statement II : Error in kinetic energy is 2. K  m v   2  K  m v  Statement -I : The number of significant figures in 0.001 is 1, while in 0.100 it is 3. Statement - II : Zeros before a non- zero significant digit are not counted while zeros after a non-zero significant digit are counted. EXERCISE - 2 : PART # I 1. D 2. A 3. B 4. B 5. A 6. B 7. B 8. A PART # II 1. D 2. A 9. B 10. ABC 11. D 12. A